Ne(g) Effuses At A Rate That Is ______ Times That Of Xe(g) Under The Same Conditions.
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Co(g) effuses at a rate that is _____ times that of xe(g) under the same conditions. 1. 1. 16, 2. 3. 16, 3. 2. 16, 4. 4. 16 Times that of xe(g) under the same conditions. Ne(g) effuses at a rate that is number rate ne ratexe ;
Ne(g) effuses at a rate that is number rate ne ratexe Let's make up a number for the rate of xe gas. Let's call it 10 ml/second. (rate co/rate xe) = sqrt (m xe/m co where m stands for molar mass xe or molar mass co. (10/x) = sqrt (131. 29/28) solve for x for rate of co then calculate how much faster/slower this is than xe. You know co should have a higher rate since the molar. Ne(g) effuses at a rate that is _____ times that of xe(g) under the same conditions. This problem has been solved! See the answer see the answer see the answer done loading.
PPT - Gases PowerPoint Presentation, free download - ID:2215121
PPT - Gases PowerPoint Presentation, free download - ID:2215121
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